Bond Enthalpies

Related Examples and Practice Problems

Additional Worked Out Examples/ Practice

  • Identifying classification types: Differentiation between elements, compounds or mixtures and homogeneous and heterogenous mixtures

  • Separation techniques: Selected and explaining limitation of appropriate separation

  • Relating Properties to Composition: Predicting classification based on descriptive properties

Topic Summary & Highlights
and Help Videos

Core Concept

Bond enthalpy (or bond dissociation energy) is the amount of energy required to break one mole of a particular type of bond in the gas phase. Average bond enthalpies are used to estimate the enthalpy change of a reaction by considering the energy required to break bonds in the reactants and the energy released when new bonds form in the products.

$\Delta H_{\text{reaction}} \approx \sum \Delta H_{\text{bonds broken}} - \sum \Delta H_{\text{bonds formed}}$

Practice Tips

  • Use Average Values Carefully: Remember, these values are averages and may differ slightly depending on molecular environment.

  • Focus on Bonds Changed: Only consider bonds that are broken in the reactants and formed in the products.

  • Account for All Bonds: Double-check that all bonds in each molecule are accounted for, especially in large molecules.

  • Sign Conventions: Energy required to break bonds is positive, while energy released from forming bonds is negative.

Topic Overview Podcast

Topic Related Resources

 LABORATORY 
 DEMONSTRATIONS 
 ACTIVITIES 
 VIRTUAL SIMULATIONS 

Steps for Calculating Reaction Enthalpy Using Bond Enthalpies

  1. Write the Balanced Equation:

    • Write the balanced chemical equation for the reaction to identify all bonds that will be broken and formed.

  2. List Bonds Broken and Formed:

    • Identify and list all the bonds in the reactants that will be broken.

    • Identify and list all the bonds in the products that will be formed.

  3. Find Average Bond Enthalpies:

    • Use a bond enthalpy table to find the average bond enthalpies for each type of bond involved.

  4. Calculate the Total Energy for Bonds Broken and Formed:

    • Multiply each bond enthalpy by the number of that bond type in the molecule, and sum for all bonds broken and all bonds formed.

  5. Calculate $\Delta H_{\text{reaction}}$​:

    • Use the formula: $\Delta H_{\text{reaction}} \approx \sum \Delta H_{\text{bonds broken}} - \sum \Delta H_{\text{bonds formed}}$

    • This gives an estimate of the enthalpy change for the reaction.

Key Concepts

  1. Bond Enthalpy (Bond Dissociation Energy):

    • The amount of energy needed to break 1 mole of bonds in a gaseous substance.

    • Represented in kJ/mol.

    • Always positive because energy is required to break bonds.

  2. Average Bond Enthalpy:

    • Bond enthalpies can vary depending on the molecular environment, so the average bond enthalpy is used as an approximation.

    • For example, the C–H bond enthalpy in methane ($\text{CH}_4$​) is slightly different from that in ethane ($\text{C}_2\text{H}_6$​), so an average value is used for general calculations.

  3. Bond Breaking and Bond Formation:

    • Bond Breaking: Endothermic process (ΔH > 0), energy is absorbed.

    • Bond Formation: Exothermic process (ΔH < 0), energy is released.

  4. Using Bond Enthalpies to Estimate $\Delta H_{\text{reaction}}$​:

    • The enthalpy change of a reaction can be estimated by subtracting the total bond energies of the bonds formed from the total bond energies of the bonds broken.

    $\Delta H_{\text{reaction}} \approx \sum \Delta H_{\text{bonds broken}} - \sum \Delta H_{\text{bonds formed}}$

Example Problem

Calculate the enthalpy change ($\Delta H_{\text{rxn}}$​) for the following reaction using the average bond energies:

$\text{CH}_4(g) + 2\text{O}_2(g) \rightarrow \text{CO}_2(g) + 2\text{H}_2\text{O}(g)$

Average Bond Energies (kJ/mol):

  • C–H: 412

  • O=O: 498

  • C=O (in $\text{CO}_2$​): 799

  • O–H: 463

Step-by-Step Solution:

  1. Write the formula for enthalpy of reaction using bond energies:

    ΔHrxn = Bonds Broken − Bonds Formed

  1. Identify bonds broken (reactants):

    • In $\text{CH}_4$: 4 C–H bonds
      Energy: 4⋅412=1648 kJ

    • In 2 $\text{O}_2$​: 2 O=O bonds
      Energy: 2⋅498=996 kJ

    Total Energy for Bonds Broken:

    1648+996=2644 kJ

  1. Identify bonds formed (products):

    • In $\text{CO}_2$​: 2 C=O bonds
      Energy: 2⋅799=1598 kJ

    • In 2 $\text{H}_2\text{O}2$: 4 O–H bonds
      Energy: 4⋅463=1852 kJ

    Total Energy for Bonds Formed:

    1598+1852=3450 kJ

  1. Calculate ΔHrxn​:

    Using the formula:

    ΔHrxn=Bonds Broken−Bonds Formed

    Substitute values:

    ΔHrxn=2644−3450

    Solve:

    ΔHrxn=−806 kJ

Video Resources