Molar Ratio

Related Examples and Practice Problems

Additional Worked Out Examples/ Practice

  • Identifying classification types: Differentiation between elements, compounds or mixtures and homogeneous and heterogenous mixtures

  • Separation techniques: Selected and explaining limitation of appropriate separation

  • Relating Properties to Composition: Predicting classification based on descriptive properties

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Core Concept

Mole ratio is the ratio of the moles of one substance to the moles of another substance in a balanced chemical equation. Mole ratios are essential in stoichiometry as they allow us to calculate the amounts of reactants and products involved in a chemical reaction.

Practice Tips

  • Memorize Common Ions: Focus on learning the common polyatomic ions, charges, and patterns.

  • Roman Numerals for Transition Metals: Practice associating transition metals with their possible charges.

  • Cross-Method for Formulas: To determine the correct formula, use the “criss-cross” method to balance charges between cations and anions.

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Key Concepts

  1. Understanding Mole Ratio:

    • The mole ratio is determined from the coefficients in a balanced chemical equation.

    • These coefficients represent the number of moles of each reactant and product.

    • For example, in the reaction 2H₂ + O₂ → 2H₂O, the mole ratio of H₂ to O₂ is 2:1, and the mole ratio of H₂ to H₂O is 2:2, which simplifies to 1:1.

Example Problem: Using Mole Ratios in a Reaction

Problem: In the reaction below, how many moles of H2O\text{H}_2\text{O}H2​O are produced if 4.0 moles of O2\text{O}_2O2​ react completely?

$2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}$

Solution:

  1. Write and Balance the Equation:

    • The equation is already balanced.

  2. Identify the Mole Ratio:

    • The mole ratio of O₂​ to H₂O is 1:2, as indicated by the coefficients.

  3. Set Up the Conversion:

    • To find the moles of H₂O from 4.0 moles of O₂, use the mole ratio:

      $4.0 \, \text{moles O}_2 \times \frac{2 \, \text{moles H}_2\text{O}}{1 \, \text{mole O}_2} = 8.0 \, \text{moles H}_2\text{O}$

Answer: 8.0 moles of H₂O are produced.

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