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Molarity
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Molar Mass
Related Examples and Practice Problems
Additional Worked Out Examples/ Practice
Identifying classification types: Differentiation between elements, compounds or mixtures and homogeneous and heterogenous mixtures
Separation techniques: Selected and explaining limitation of appropriate separation
Relating Properties to Composition: Predicting classification based on descriptive properties
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Topic Summary & Highlights
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Core Concept
Molar mass is the mass of one mole of a substance. It is usually expressed in grams per mole (g/mol).
Calculating Molar Mass:
To calculate the molar mass of a substance, you need to add up the atomic masses of all the atoms in a molecule.
Practice Problem 1: Calculate the Molar Mass of Sulfuric Acid (H2SO4\text{H}_2\text{SO}_4H2SO4)
Write the Formula: H2SO4\text{H}_2\text{SO}_4H2SO4 (two hydrogen atoms, one sulfur atom, and four oxygen atoms).
Find Atomic Masses:
Hydrogen (H): 1.01 g/mol
Sulfur (S): 32.07 g/mol
Oxygen (O): 16.00 g/mol
Multiply by the Number of Atoms:
Hydrogen: 1.01 g/mol×2=2.02 g/mol1.01 \, \text{g/mol} \times 2 = 2.02 \, \text{g/mol}1.01g/mol×2=2.02g/mol
Sulfur: 32.07 g/mol×1=32.07 g/mol32.07 \, \text{g/mol} \times 1 = 32.07 \, \text{g/mol}32.07g/mol×1=32.07g/mol
Oxygen: 16.00 g/mol×4=64.00 g/mol16.00 \, \text{g/mol} \times 4 = 64.00 \, \text{g/mol}16.00g/mol×4=64.00g/mol
Add Up the Masses:
Molar Mass of H2SO4=2.02 g/mol+32.07 g/mol+64.00 g/mol=98.09 g/mol\text{Molar Mass of H}_2\text{SO}_4 = 2.02 \, \text{g/mol} + 32.07 \, \text{g/mol} + 64.00 \, \text{g/mol} = 98.09 \, \text{g/mol}Molar Mass of H2SO4=2.02g/mol+32.07g/mol+64.00g/mol=98.09g/mol
Answer: The molar mass of sulfuric acid (H2SO4\text{H}_2\text{SO}_4H2SO4) is 98.09 g/mol.
Practice Problem 2: Determine the Molar Mass of Ammonium Phosphate ((NH4)3PO4)(\text{(NH}_4\text{)}_3\text{PO}_4)((NH4)3PO4)
Write the Formula: (NH4)3PO4(\text{NH}_4)_3\text{PO}_4(NH4)3PO4 (three ammonium ions, each with one nitrogen and four hydrogens, and one phosphate group with one phosphorus and four oxygens).
Find Atomic Masses:
Nitrogen (N): 14.01 g/mol
Hydrogen (H): 1.01 g/mol
Phosphorus (P): 30.97 g/mol
Oxygen (O): 16.00 g/mol
Multiply by the Number of Atoms:
Ammonium Group (NH4\text{NH}_4NH4) has 1 nitrogen and 4 hydrogens:
Nitrogen: 14.01 g/mol×3=42.03 g/mol14.01 \, \text{g/mol} \times 3 = 42.03 \, \text{g/mol}14.01g/mol×3=42.03g/mol
Hydrogen: 1.01 g/mol×12=12.12 g/mol1.01 \, \text{g/mol} \times 12 = 12.12 \, \text{g/mol}1.01g/mol×12=12.12g/mol
Phosphate Group (PO4\text{PO}_4PO4) has 1 phosphorus and 4 oxygens:
Phosphorus: 30.97 g/mol×1=30.97 g/mol30.97 \, \text{g/mol} \times 1 = 30.97 \, \text{g/mol}30.97g/mol×1=30.97g/mol
Oxygen: 16.00 g/mol×4=64.00 g/mol16.00 \, \text{g/mol} \times 4 = 64.00 \, \text{g/mol}16.00g/mol×4=64.00g/mol
Add Up the Masses:
Molar Mass of (NH4)3PO4=42.03 g/mol+12.12 g/mol+30.97 g/mol+64.00 g/mol=149.12 g/mol\text{Molar Mass of (NH}_4\text{)}_3\text{PO}_4 = 42.03 \, \text{g/mol} + 12.12 \, \text{g/mol} + 30.97 \, \text{g/mol} + 64.00 \, \text{g/mol} = 149.12 \, \text{g/mol}Molar Mass of (NH4)3PO4=42.03g/mol+12.12g/mol+30.97g/mol+64.00g/mol=149.12g/mol
Answer: The molar mass of ammonium phosphate ((NH4)3PO4)(\text{(NH}_4\text{)}_3\text{PO}_4)((NH4)3PO4) is 149.12 g/mol.
FYI -
Molar Mass and Molecular Weight: Molar mass and molecular weight are often used interchangeably, but they are not exactly the same thing. Molecular weight is the sum of the atomic weights of all the atoms in a molecule, whereas molar mass is the mass of one mole of that molecule.
Molar Mass and Avogadro's Number: Avogadro's number is the number of particles in one mole of a substance (6.02 x 10^23). The molar mass of a substance is directly related to Avogadro's number, as one mole of any substance will always have a mass equal to its molar mass.